tli8322 tli8322
  • 04-08-2022
  • Mathematics
contestada

How do I solve “1+2+3+4+5+…100=“
A. 1010
B. 5050
C. 5000
D. 1000

Respuesta :

jetsungyembo
jetsungyembo jetsungyembo
  • 04-08-2022

Answer:

5050

Step-by-step explanation:

we know that 100/2 is 50 and 50 x 100 is 5000

so now another 50 is remaining but we can't multiply but add so

1+2+3+4+5...100 = in simple form= 50x100+50=5050//

Answer Link

Otras preguntas

I'm what part of the cell does cellular respiration occur
Which is not a quality of good friendship
Which of the following is an advantage of the sole proprietorship form of ownership? A. Unlimited liability B. Control over the business C. Limited liability D
What is the value of b in the equation (yb) 4 = 1/24y
Given the equation y = 5x - 1, what are the intercepts? x-intercept = -1 and y-intercept = 1/5 x-intercept = 1 and y-intercept = -1/5 x-intercept = and y-inter
Which verb form correctly completes this sentence? Yo ________ ganar el partido de tenis. pudiste pude pudimos pudo
¿Cuál es el significado del verbo en la siguiente frase? Quise comprar una nueva casa. a) I wanted to b) I tried to c) I wished
What is the value of x? Enter your answer in the box. x =
Which statement indicates that an aquatic organism demonstrates k-selection
pleasse help thank you.