kccasher123owmzpr
kccasher123owmzpr
01-05-2018
Mathematics
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Answer this question
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Аноним
Аноним
01-05-2018
With the given equation, you have to determine the defined range.
Simplify the equation using cross-multiply.
W^2=4(2w-3)
Move the expression to the left side and change its sign.
w^2-4(2w-3)=0
Next, Distribute "-4" through the parenthesis
w^2-8w+12=0
Solve by using the quadratic equation. "x= +- Sqr (b)^2-4(a)(c) / 2(a)"
-(-8)+-Sqr (-8)^2-4(1)(12) / 2(1)
solve the equation
w=8 +- Sqr of 16
You got to separate the equation into two other equations and simplify it.
w= 8+4/2 +6
w=8-4/2=2
The correct answer is 6 and 2.
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